"Whereas at the outset geometry is reported to have concerned itself with the measurement of muddy land, she now handles celestial as well as terrestrial problems. She has extended her domain to the furthest bounds of space." -- (Hodder and Stoughton, The Story of Euclid, 1901) Fibonacci (Leonardo of Pisa, 1170-1250). Fibonacci is known for the sequence that bears his name: 1,1,2,3,5,8,13,21,34,55,89,144,... . This amazing sequence appears in a number of natural and human-made creations. It is less well known that Fibonacci studied under Islamic teachers as a result of being with his merchant father on many trips from Italy to what is now Algiers in North Africa. As he grew older, Fibonacci traveled throughout the Mediterranean area, frequently meeting with mathematicians and scholars. Upon returning to his homeland in 1200, he began to write manuscripts that incorporated and expanded the mathematics he had learned in the Islamic world, which was far superior to the cumbersome Roman numeral arithmetic in use at that time. What did Herkimer's girl friend, Edith, say when she learned he had been dating Kate? Answer: "He can't have his Kate and Edith too." Herky's friends: BARB BELL...she was a talented weightlifter. SUE PREME...this girl did everything extremely well. ASSIGNMENT #54 Reading: Section 9.2 (pages 472-477 plus Summary, page 479). Exercises: 9.14 (page 471), 9.15, 9.17, 9.20 (page 477). Think about what you are writing. Don't get sloppy here.

You are in Section 9.2.

Read this section carefully. Lots of importantthoughts and formulas here.

Note that the formulas deal with proportions, notcounts. If you have a sample of size N from a population withproportion p, then:

For counts, we have

mx = Np and sx = sqrt[Np(1-p)], where x =0,1,2,3,....,N

Now, if you are talking about proportions, you arebasically just dividing values of x by N, to achieve p(hat) values.The values p(hat) are 0/N, 1/N, 2/N, ...., (N-1)/N, N/N.

Forproportions, we have

mp(hat) = mx/N = (Np)/N = p andsp(hat) = sx/N = (sqrt[Np(1-p)])/N =sqrt[Np(1-p)/N2] = sqrt[p(1-p)/N].

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Text:
The Practice of Statistics, by Yates, Moore, McCabe. New York,W.H. Freeman and Company, 1999. (ISBN 0-7167-3370-6)

Supplemental books:
The Cartoon Guide to Statistics, by Gonick and Smith. NewYork, HarperCollins Publishers, 1993. (ISBN 0-06-273102-5)
How to Lie with Statistics, by Darrell Huff. New York, W.W.Norton & Company, 1982 (ISBN 0-393-09426-X)